Math, asked by niallquadros, 1 year ago

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Answered by iamswarnarka
2

Answer:

Step-by-step explanation:

Let m=man's age

Then s =son's age = m-32

Man's age ten years ago was m-10

Son's age ten years ago was m - 32 -10=m-42

But we also know man 10 years ago = 3* son 10 years ago

So m-10=3%2A%28m-42%29

Distribute and simplify:

M

m-10=3m-3%2842%29=3m-126

m-10=3m-126

 

Subtract m from both sides

-10=2m-126

Add 126 to both sides

116=2m and divide by 2 on both sides to get m =58.

So the man is now 58 years old. Going to the top, we find his son is 32 years younger, so his son is 58-32=26.

To check, go back ten years: the man was 48 and his son was 16 and 48=3*16.

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