Question

pls answer this question​

Answer 1

Answer:

a) 30 m/s

b) 60 kg m/s

Explanation:

Given :

• Force acting on the body = 15 Newtons

• Mass of the object = 2 kg

• Time taken = 4 seconds

• Initial velocity = u = 0 m/s

To find :

• Velocity acquired by the body

• Change in momentum of the body

F = mass(final velocity - Initial velocity) /time

15 = 2(v-0)/4

60=2v

v = 60/2

v = 30 m/s

a) 30 m/s

Change in momentum = mv-mu

Change in momentum = 2×30 - 2×0

Change in momentum = 60-0

Change in momentum = 60 kg m/s

b) 60 kg m/s

Answer 2

Answer:

Given:

• A force of 15 N acts on a body of mass 2Kg for 4s, Initally at rest.

Find:

Calculate:

1. The velocity acquired by the body.
2. Change in momentum of the body.

Know terms:

• Initial velocity = (u)
• Time taken = (t)
• Final velocity = (v)
• Mass = (M)

Using formula:

★ ${\sf{\underline{\boxed{\orange{\sf{F = \dfrac{M(v - u)}{t}}}}}}}$

Calculations:

⇒ $\bold{15 = \dfrac{2(v-0)}{4}}$

⇒ $\bold{60=2v}$

⇒ $\bold{\dfrac{60}{2}}$

⇒ ${\sf{\underline{\boxed{\red{\sf{v = 30 \: m/s}}}}}}$

Using formula:

★ ${\sf{\underline{\boxed{\orange{\sf{Momentum's \: change = mv - mu}}}}}}$

Calculations:

⇒ $\bold{2 \times 30 - 2 \times 0}$

⇒ $\bold{60-0}$

⇒ ${\sf{\underline{\boxed{\red{\sf{60 \: kg \: m/s}}}}}}$