Question

pls answer this question​

Answer 1

Answer:

-0.0032 Newtons

Explanation:

Given :

• Mass of the balloon in air = m = 2 grams = 0.002

• Initial velocity of the air with which it comes out = u = 4 m/s

• Final velocity = v = 0 m/s (As the air stops coming out finally as no air is there)

• Time taken = t = 2.5 seconds

To find :

• Average force acting on the balloon

Force = m(v-u) / t

Force = 0.002(0-4)/2.5

Force = 0.002×-4/2.5

Force = - 0.008/2.5

Force = -0.0032 Newtons

The average force acting on the balloon is equal to -0.0032 Newtons

Answer 2

Answer:

Given:

• A balloon of 2g of air. A small hole is pierced into it. The air comes out with a velocity of 4 ms-1.

Find:

• If the balloon shrinks completely in 2.5 seconds, find the average force acting on the balloon.

Know terms:

1. Force = (F)
2. Mass = (m)
3. Initial velocity = (u)
4. Final velocity = (v)
5. Time taken = (t)

Using formula:

★ ${\sf{\underline{\boxed{\orange{\sf{F = \dfrac{m (v-u)}{t} }}}}}}$

Calculations:

⇒ $\bold{F = \dfrac{0.002(0-4)}{2.5}}$

⇒ $\bold{F = \dfrac{0.002 \times -4}{2.5}}$

⇒ $\bold{F = \dfrac{- 0.008}{2.5}}$

⇒ ${\sf{\underline{\boxed{\red{\sf{F = -0.0032 \: N}}}}}}$

Therefore, -0.0032 Newton is the average force acting on the balloon.