Question

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Answer 1

Step-by-step explanation:

If a circle has radius r then the circumference is 2πr . If 2πr=10 cm then r=102π cm=5π cm .

The area of circle with radius r is πr2 , so if r=5π cm the area is π(5π)2 cm2=25π cm2 .

The height of an equilateral triangle is 3√2 times the side length, so if the height is h then the side length is 23√h .

The area of a triangle is 12×base×height , so if the height is h and the base is 23√h then the area is 12×23√h×h=13√h2 .

So if 13√h2=25π cm2 , then h2=253√π cm2 ,

∴h=253√π−−−−√ cm=53–√π−−−√ cm≈3.7126 cm

Answer 2

Answer:

Circumference of circle = 10cm

2πr = 10cm

2×22/7×r = 10cm

44/7×r = 10cm

r = 10×7/44

r = 70/44cm

Area of circle = πr×r

= 22/7×70/44×70/44

= 15400/1936

= 7.95

Area of equilateral triangle = 7.95

1.73/4×(Side) square = 7.95

(Side) square = 7.95×4/1.73

(Side) square = 3180/173

(Side) square = 18.38

Side = ✓18.38

Side = 4.29cm

Area = 1/2× base × height

7.95 = 1/2× 4.29 × height

height = (7.95×2)/4.29

height = 15.9/4.29

height = 3.70 cm

Step-by-step explanation:

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