Physics, asked by liza1907, 6 months ago

pls answer this question​

Attachments:

Answers

Answered by gamerchiru395
3

Answer:

Hey mate here is your answer

8) Given:-

Initial velocity (u) = 22.4m/s

Final velocity (v) = 0

Time = 2.55sec

To find:-

Accleration and distance

By applying, v - u = at

0 - 22.4 = a×2.55

22.4 = 2.55a

a = 22.4/2.55

= 8.7843m/s^2.

By applying, v^2 - u^2 = 2as

0 - 501.76 = 2×8.7843×s

501.76 = 17.5686s

S = 28.56m.

9) Given:-

Initial velocity (u) = 18.5m/s

Final velocity (v) = 46.1m/s

Time = 2.47sec

To find:-

Accleration and distance

By applying v - u = at

46.1 - 18.5 = a×2.47

27.6 = 2.47a

a = 27.6/2.47

= 11.174089m/s^2.

By applying, v^2 - u^2 = 2as

2125.21 - 342.25 = 2×11.174089×s

1782.96 = 22.348s

S = 79.78163m.

10) Given:-

Initial velocity (u) = 36km/hr = 10m/s

Final velocity (v) = 0

Time = 5sec

To find:-

(i) Accleration

By applying v - u = at

0 - 10 = a×5

10 = 5a

a = 10/5

= 2m/s^2.

(ii) Distance

By applying v^2 - u^2 = 2as

0^2 - 10^2 = 2×2×s

100 = 4s

S = 100/4

= 25m.

Similar questions