Question

Pls answer this question!!

Answer 1

Answer:

hmmmmmmmmm can't under stand

Answer 2

draw perpendicular XZ from X on PQ

since XP = XQ

∆ XPQ is an isosceles triangle.

in isosceles triangle, perpendicular from vertex bisects the base

thus, ZP = ZQ

ZP + PY = ZQ + PY

ZP + PY = ZQ + QR. ( PY = QR)

ZY = ZR

now in ∆ XYR

perpendicular XZ bisects YR

hence, ∆ XYR is an isosceles ∆

so XY = XR

proved

(note: we can also prove last part by proving triangles XZY and XZR congruent)