Question

pls answer this question

Answer 1

$\cos( \alpha ) = 0.6 = (6 \div 10) \\ \cos( \alpha ) = 3 \div 5 \\ hence \: \sin( \alpha ) = 4 \div 5 \\ \tan( \alpha ) = 4 \div 3 \\ \sec( \alpha ) = 5 \div 3 \\ \cot( \alpha ) = 3 \div 4 \\ now \: put \: these \: in \: questions \: u \: will \: get \: \\ (4 - 4) \div (5 - 3) = indefinite \: form \:$