Question

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Answer 1

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Answer 2

Equation of circle (x−h)²+(y−k)²=r²

⇒(4−h)²+(1−k)²=r² ...(1)

⇒(6−h)²+(5−k)²=r² ...(2)

solving the above 2 equations, we get,

h+2k=11 ...(3)

given, 4h+k=16 ...(4)

solving the above 2 equations, we get,

h=3,k=4

substituting the above values in (1), we get,

(4−3)²+(1−4)²=r²

∴r= √10

Hence, the equation is,

(x−3)²+(y−4)²=(√10)²

x²+y²−6x−8y+15=0