Chemistry, asked by Anonymous, 5 months ago

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Answered by BʀᴀɪɴʟʏAʙCᴅ
3

\huge\mathcal{\boxed{\fcolorbox{lime}{orange}{SOLUTION;-}}} \\

☃️ The energy of electron in Bohr's model is directly proportional to Z²/n² .

☃️ Therefore the energy of electron in 3nd orbit of He+ is 4 times the energy of electron in 3nd orbit of Hydrogen .

\bf{\color{aqua}\implies} Energy of the third orbit of H-atom is '-4x kJ/mol' .

[Note → Bohr's model can be applied to single electrons system only .]

We know that,

\sf\pink{\implies\:Energy\:(E)\:\propto\:\dfrac{Z^2}{n^2}\:} \\

  • Here, Z is same for second orbit of H-atom & third orbit of H-atom .

\sf{\implies\:\dfrac{E_2}{E_3}\:=\:\dfrac{n^2_3}{n^2_2}\:} \\

\sf{\implies\:\dfrac{E_2}{-4x}\:=\:\dfrac{3^2}{2^2}\:} \\

\sf{\implies\:E_2\:=\:\dfrac{9}{4}\times{-4x}\:} \\

\sf\red{\implies\:E_2\:=\:-9x\:KJ.mol^{-1}} \\

The energy of second orbit of H-atom will be '-9x KJ/mol' .

Answered by Anonymous
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