Math, asked by abdulhadicoder, 3 months ago

Pls answer this question ☝️

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Answers

Answered by mssobihabib74
1

hope you got it the answer ......

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Answered by s8983588874
1

Step-by-step explanation:

LHS

1−cotθ

tanθ

+

1−tanθ

cotθ

=

1−

tanθ

1

tanθ

+

1−tanθ

tanθ

1

=

tanθ

tanθ−1

tanθ

+

tanθ(1−tanθ)

1

=

tanθ−1

tan

2

θ

+

tanθ(1−tanθ)

1

=

tanθ−1

tan

2

θ

tanθ(tanθ−1)

1

=

tanθ(tanθ−1)

tan

3

θ−1

=

tanθ(tanθ−1)

(tanθ−1)(tan

2

θ+tanθ+1)

=

tanθ

tan

2

θ+tanθ+1

=

tanθ

tan

2

θ

+

tanθ

tanθ

+

tanθ

1

=tanθ+1+cotθ

=1+

cosθ

sinθ

+

sinθ

cosθ

=1+

sinθcosθ

sin

2

θ+cos

2

θ

=1+

sinθcosθ

1

=1+secθcosecθ = RHS

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