Math, asked by sriramya9012, 3 months ago

pls answer this question​

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Answered by Anonymous
8

( { (\sin\theta )}^{2}  +  \frac{1}{1 +  { (\tan\theta) }^{2} } ) \\ \implies \: ( \:  { (\sin\theta) }^{2}  +  \frac{1}{ { (\sec\theta) }^{2} } ) \\ \implies \:  { (\sin\theta) }^{2}  +  { (\cos\theta) }^{2}  = 1

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