pls answer this question
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The solution is in the attachment.
Note : Use the sign of " = " in 1st figure.
Note : Use the sign of " = " in 1st figure.
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Hey friend,
Here is your answer,
______________________________________________________________
√(a²-b²) + a ÷ √(a²+b²) - b
√(a²+b²) + b √(a²+b²) - a
=> [ √(a²+b²) + a ] * [ √(a² + b²) - a ]
[ √(a²+b²) + b ] * [ √(a² + b²) - b ]
=> [√(a² + b²)]² - a²
[√(a² + b²)]² - b²
=> a² + b² - a²
a² + b² - b²
=> b²
a²
______________________________________________________________
Hope this helped you !!
Please mark as brainliest !!
Here is your answer,
______________________________________________________________
√(a²-b²) + a ÷ √(a²+b²) - b
√(a²+b²) + b √(a²+b²) - a
=> [ √(a²+b²) + a ] * [ √(a² + b²) - a ]
[ √(a²+b²) + b ] * [ √(a² + b²) - b ]
=> [√(a² + b²)]² - a²
[√(a² + b²)]² - b²
=> a² + b² - a²
a² + b² - b²
=> b²
a²
______________________________________________________________
Hope this helped you !!
Please mark as brainliest !!
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