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First of all lets find the total Resultant Resistance
Since, R2 , R3 , R4 are connected in parallel so
1/R= 1/R2 + 1/R3 + 1/R4
1/R = 1/1 +1/2 +1/3
1/R = 11/6
R = 6/11
Now this new R and R1 and R5 are connected in series
So,
Req = 6/11 + 2 +2 = 50/11 ohm
Now, lets find the total current drawn by this resistance
I = V/R
= 9/(50/11)
= 99/50 Ampere
At last
V at R1 = I × R1
= (99/50) × 2 = 3.96 volt
V at R2 , R3 , and R4 will be same
So,
V = I R = (99/50)(6/11) = 1.08 volt
V at R5 = I x R5 = (50/11) × 2 = 3.96 volt
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