Question

pls answer this question​

Answer 1

Answer:

Ok, first you're going to have to factor the function inside the log:

2x^2 +8x+8, you can use the quadratic formula and you'll get these factors:

(2x+4)(x+2)

Now you have log2 ((2x+4)(x+2))

When you have multiplication inside logs that is equal to sdding logs

log2(2x+4) + log2 (x+2)

Now from the first part you can factor out a 2

2(x+2)

log (2) + log (x+2) + log (x+2)

And that's as far as it can expand