Physics, asked by chweety1, 1 year ago

pls answer this question

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Answered by MOSFET01
1
v=30m/s
u=0 m/s
a=10m/s²
t=1.5 s

Then sin A = 1.5×10/30 = 15/30= 1/2

A= sin inverse(0.5)

A= 30°

Range =v² sin 2A/a

Range =(30)² sin 2(30)° / 10

= 900sin 60°/10
= 900 √3/2/10
= 450√3/10
= 45√3

MOSFET01: also in my ans m
chweety1: tq bro
MOSFET01: welcome
kevinujunioroy492d: no bro
kevinujunioroy492d: thats not m^2 i tried erase that
kevinujunioroy492d: thats m only
Answered by kevinujunioroy492d
1
it is very simple i will give u a relation between RANGE AND MAXIMUM HEIGHT
U can solve many problems with that


relation between R and H

R/H =4cot(theta)

{theta = angle between velocity and horizontal
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MOSFET01: 45 √3 m
MOSFET01: :-)
MOSFET01: m² replace by m
chweety1: tq bro
chweety1: bro can u solve the problem
MOSFET01: ??
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