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Let, AE and CD intersects each other at Point O.
Now, In tr.AOD and tr.EOC
angle x = angle y (given)
angle AOD = angle EOC ( V.O.A.)
AD=CE (half of the equal sides are always equal).
So, by AAS congruency rule,
Tr. AOD is congruent to Tr. EOC
By, CPCT
we have, angle A = angle C.
Now,
In Tr. ABE And Tr. CBD
AB = BC (given)
angle A = angle C (proved above)
angle B = angle B ( common angle)
so, by AAS congruecy rule,
Tr. ABE is congruent to Tr. CBD
By CPCT,
we have,
AE = CD.
Hence, Proved.
Hope this will help you. ✌✌☺
Now, In tr.AOD and tr.EOC
angle x = angle y (given)
angle AOD = angle EOC ( V.O.A.)
AD=CE (half of the equal sides are always equal).
So, by AAS congruency rule,
Tr. AOD is congruent to Tr. EOC
By, CPCT
we have, angle A = angle C.
Now,
In Tr. ABE And Tr. CBD
AB = BC (given)
angle A = angle C (proved above)
angle B = angle B ( common angle)
so, by AAS congruecy rule,
Tr. ABE is congruent to Tr. CBD
By CPCT,
we have,
AE = CD.
Hence, Proved.
Hope this will help you. ✌✌☺
Anjalithehappy:
thank you
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