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The total weight is 121/2
Let weight of box A be a
weight of box B be 7/2 + a
weight of box C be 16/3 + 7/2 + a as per given in question
Since total weight = weight of box A + weight of box B + weight of box C
121/2 = a + 7/2 + a + 16/3 + 7/2 + a
121/2 = 3a + 14/2 + 16/3
121/2 = 3a + 7 + 16/3
121/2 = 9a/3 + 21/3 + 16/3
Now by shifting both LCM
363 = 42 + 32 + 18a
289 = 18a
289/18 = a Ans
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