Math, asked by hariharan108, 1 year ago

pls answer this question

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Answered by siddhartharao77
2

Answer:

Option(C)

Step-by-step explanation:

Given, Parallel sides of trapezium are 20 cm and 10 cm.

Its non-parallel sides are equal being 13 cm each.

From figure:

AD = BC = 13 cm.

D = CN = x cm.

∠DMA = ∠CNB = 90°

∴ AM = BN  --- (i)

MN = 10 cm.

Since, AB = AM + MN + NB

⇒ 20 = AM + 10 + BN

⇒ AM + BN = 20 - 10 = 10

⇒ 2 BN = 10

⇒ BN =5 cm.

Therefore, AM = BN = 5 cm.

By Pythagoras theorem,

⇒ (13)² = (5)² + (x)²

⇒ 169 - 25 = x²

⇒ x = 12 cm.

Hence, Distance between the parallel sides = 12 cm.

Therefore, Area of trapezium = (1/2) * Sum of parallel sides * Altitude

                                                 = (1/2) * (20 + 10) * 12

                                                 = 180 cm²


Area of trapezium = 180 cm²


Hope it helps!

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Answered by Siddharta7
1

Answer:

C

Step-by-step explanation:

The answer is explained below.

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