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- Question⇒ If abcd be a rectangle and p be any point in the plane of the rectangle,then prove that pa^2+pc^2=pb^2+pd^2
Step-by-step
- PD² - DA'² = PA'² = PA² - AA'²
- similarly,
- PC² - CC'² = PC'² = PB² - BC'²
- hence,
- PD² - PA² = PC² - PB²
- ⇒PD² + PB² = PC² + PA²
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