Question

pls answer this question​

Answer 1

m angle A is half of m (arcBC)

Hence 2Angle A= m arc(BC)

2×30°= m arc(BC)

60°=Marc( BC)

as given Side AB is congurent to side AC

Angle B congurent angle C.... conv of isosceles ∆

hence angle C is 75°

therefore m arc (AB) is twice angle C

m arc (AB) =2×75°

Marc (AB)= 150°....

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Answer 2

Answer:

Step-by-step explanation:

m(arcBC)=1/2×angle BAC [inscribed angle theorem]

=1/2×30°

=15°

ChordAB=CHORDAC

ArcAB=ArcAC

m(arcAB)+m(arcAC)=360-m(arcBC)

2m(arcAB)=360-15

m(arcAB)=345/2=172.5°