Question

pls answer this question ( class 9 )​

Answer 1

Answer:

the answer is so easy and the answer iis 1

Answer 2

Step-by-step explanation:

${x}^{3} + \frac{1}{ {x}^{3} } ={ (x + \frac{1}{x} )}^{3} - 3x \times \frac{1}{x} (x + \frac{1}{x} ) \\ = { (x + \frac{1}{x} )}^{3} - 3 (x + \frac{1}{x} )$

$x + \frac{1}{x} = \sqrt{3} + \sqrt{2} + \frac{1}{ \sqrt{3} + \sqrt{2} }$

$x + \frac{1}{x} = \sqrt{3} + \sqrt{2} + \frac{1}{ \sqrt{3} + \sqrt{2} } \\ = \sqrt{3} + \sqrt{2} + \frac{ \sqrt{3} - \sqrt{2} }{3 - 2} \\ = 2 \sqrt{3}$

${x}^{3} + \frac{1}{ {x}^{3} } = ({2 \sqrt{3} })^{3} - 3(2 \sqrt{3} ) \\ = 0$