Question

pls answer this question correctly​

Answer 1

Answer:

$\huge \pink{ \sqrt{2} \pi}$

Explanation:

We know that

$pressure = \frac{force}{area} \\ \\ \implies \: area = {force \over \: pressure} \\ \\ \implies \: \pi {r}^{2} = \frac{200}{314 } \\ \\ \implies {r}^{2} = \frac{314}{200\pi} = \frac{314}{200 \times 3.14} \\ \\ \implies {r}^{2} = \frac{1}{2} \\ \\ \implies r = \frac{1}{ \sqrt{2} }$

So circumference

$= 2\pi r = 2\pi \times \frac{1}{ \sqrt{2} } = \sqrt{2} \pi$

Answer 2

Answer:

$\large \dag$ Question :-

A cylindrical block of weight 314N is placed on horizantal surface .If it excert pressure of 200 Pa on the surface .Then Find the circumference of the circular part of cylinder .

$\large \dag$ Answer :-

$\sf\tt\large{\red {\underline {\underline{⚘\;The \;circumference \;of \;the \;circular \;cylinder \;is:}}}}$

$\sqrt{2} \pi$

$\large \dag$ Solutions :-

Hey mate,

In the question given that,

$\small\text{First let verify yourquestion. In the question given acylindrical block of weight 314N is placed on horizontal surface .If it exert pressure of 200 Pa on the surface.}$

$\small\text{Here first we shouldcome to know what formulae we should want toput to get the circumference of circular part of cylinder}$

$\small\text{Here we know that}$

• $\small\text{Pressure =force /area }$

$\small\text{Taking here area to LHS and pressure to RHS side}$

$\small\text{we get,}$

• $\small\text{area =force/pressure}$

• pi r^2 = 200/314

• r^2=314/200 pi

$\small\text{Here taking}$

$\pi$ $\small\text{value as 3.14}$

$\small\text{We get,}$

• r^2=1/2
• $r = \frac{1}{ \sqrt{2} }$

$\small\text{So,}$

• $\small\text{Here circumference =}$
• $2\pi \: r$
• $2\pi \times \frac{1}{ \sqrt{2} } = \sqrt{2\pi}$

$\small\text{Hence ,this is the perfect answer to your question}$

$\large \dag$ Hope it helps u mate .

$\large \dag$ Thank you .