Math, asked by aslamm, 16 days ago

pls answer this question correctly. We get the quotient as 4354 on dividing 65,314 by 15. We can see that 65,314 is not perfectly divisible by 15 as we get a non-zero remainder. Thus, after packing the blankets equally in 4354 boxes, some blankets would still be left. So, what will be the minimum number of boxes needed to pack all the blankets?

Answers

Answered by jagruti6551
0

Answer:

Throwing a die twice and throwing two dice simultaneously are treated as the same experiment.

Sample space ={(1,1),(1,2),(1,3),(1,4),(1,5),(1,6)

(2,1),(2,2),(2,3),(2,4),(2,5),(2,6)

(3,1),(3,2),(3,3),(3,4),(3,5),(3,6)

(4,1),(4,2),(4,3),(4,4),(4,5),(4,6)

(5,1),(5,2),(5,3),(5,4),(5,5),(5,6)

(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)}

i) P(5 will not come up either time)= Number of times 5 does not show divided by total number of outcomes

P(5 will not come up either time)=

36

25

ii) P(5 will come up at least once)= Number of times 5 shows up at least once divided by total number of outcomes

P(5 will come up at least once)=

36

11

Answered by bcsharma1945
0

Answer:

1 box more needed to pack the blanket.

remainder=4

Step-by-step explanation:

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