Question

pls answer this question
Fast​

Answer 1

by pythagoras property

7^2+x^2=25^2

x^2=625-49

     =576

x^2=24^

x=24

so the distance between their tops are 24 m

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Answer 2

$\Large{\underline{\underline{\mathfrak{\bf{Solution}}}}}$

$\Large{\underline{\mathfrak{\bf{\pink{Given}}}}}$

• Height of first pole = 31 m
• Height of second pole = 24 m
• Distance between their topes = 25 m

$\Large{\underline{\mathfrak{\bf{\pink{Find}}}}}$

• Distance between their bases on the ground

$\Large{\underline{\underline{\mathfrak{\bf{Explanation}}}}}$

In , Diagram ,

• AD = 31 m , is a first pole
• CE = 24 m , is a second pole
• AC = 25 m, distance between first pole and second pole

Here, CE = BD = 24 m

Then,

• AB = AD - BD
• AB = 31 - 24
• AB = 7 m

$\Large{\underline{\mathfrak{\bf{\pink{Calculate}}}}}$

• BC = ?

$\Large{\underline{\mathfrak{\bf{\orange{By\:Pythagoras\:theorem}}}}} \\ \\ \boxed{\sf{\green{\:(Hypotenuse)^2\:=\:(Base)^2+(Perpendicular)^2}}} \\ \\ \mapsto\sf{\:(AC)^2\:=\:(BC)^2+(AB)^2} \\ \\ \mapsto \sf{\:(BC)^2\:=\:(AC)^2-(AB)^2} \\ \\ \mapsto\sf{\:(BC)^2\:=\:(25)^2-(7)^2} \\ \\ \mapsto\sf{\:(BC)^2\:=\:625-49} \\ \\ \mapsto\sf{\:(BC)^2\:=\:576} \\ \\ \mapsto\sf{\:(BC)\:=\:\sqrt{576}} \\ \\ \mapsto\sf{\red{\:(BC)\:=\:24\:m}}$

But, here ,

• BC = DE

So,

• DE = 24 m

$\Large{\underline{\mathfrak{\bf{\orange{Thus}}}}}$

Distance between their bases on the ground = 24 m