Question

pls answer this question fast​

Answer 1

Step-by-step explanation:

it's given that,

angle ABC =68° and angle ACB = 48°

as BO and OC are angle bisectors,

angle OBC= 62/2=31°

angle OCB=48/2=24

according to angle sum property,

31+24+BOC=180°

55+BOC=180°

angle BOC=180-55

angle BOC=125°

Answer 2

$\huge\mathcal{\pink{A}}\huge\mathcal{\purple{N}}\huge\mathcal{\green{S}}\huge\mathcal{\blue{W}}\huge\mathcal{\red{E}}\huge\mathcal{\orange{R}}$

$\huge\underline\mathrm{GiVeN}$

• ∠ABC = 62°

• ∠ACB = 48°

$\huge\underline\mathrm{To \: FiNd}$

• ∠BOC = ?

$\huge\underline\mathrm{SoLuTiOn}$

BO is a bisector of ∠B. So, ∠ABO = ∠OBC

CO is a bisector of ∠C. So, ∠OCB = ∠AOC

Let ∠ABO and ∠OBC be x.

➨∠ABO + ∠OBC = ∠ABC

➨ x + x = 62°

➨ 2x = 62°

➨ x = 62°/2

➨ x = 31°

Therefore, ∠ABO = ∠OBC = 31°

Let ∠OCB and ∠AOC be y.

➨∠OCB + ∠AOC = ∠ACB

➨ x + x = 48°

➨ 2x = 48°

➨ x = 48°/ 2

➨ x = 24°

Therefore, ∠OCB = ∠AOC = 24°

Now, In△BOC

➨ ∠OCB + ∠OBC + ∠BOC = 180° [Angle Sum Property of triangle ]

➨31° + 24° + ∠BOC = 180°

➨55° + ∠BOC = 180°

➨∠BOC = 180° - 55°

➨∠BOC = 125°

Therefore, ∠BOC = 125°

hope it helps you.....✌