Question

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Answer 1

Hope it helps
Is it correct

Answer 2

given:

$\frac{1}{ \sqrt{2} + \sqrt{3} } - \frac{1}{ \sqrt{2} - \sqrt{3} }$
→ on rationalizing the denominator we get,

$= \frac{( \sqrt{2 } - \sqrt{3}) - ( \sqrt{2} + \sqrt{3}) }{( \sqrt{2} - \sqrt{3} )( \sqrt{2} + \sqrt{3}) }$

→ we know that,

${a}^{2} - {b}^{2} = (a + b)(a - b)$
$= \frac{ (\sqrt{2} - \sqrt{3}) - ( \sqrt{2} + \sqrt{3} ) }{2 - 3} \\ \\ = \frac{ \sqrt{2} - \sqrt{3} - \sqrt{2} - \sqrt{3} }{ - 1} \\ \\ = \frac{ - \sqrt{3} - \sqrt{3} }{ - 1} \\ \\ = \frac{ - 2 \sqrt{3}}{ - 1} \\ \\ = 2 \sqrt{3}$

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