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sum of interior angle of a polygon is equal to
180(n-2).
where n is no. of sides..
according to the given question..
180(n-2)=3060
then.n=17+2=19sides
180(n-2).
where n is no. of sides..
according to the given question..
180(n-2)=3060
then.n=17+2=19sides
Answered by
2
Sum of interior angles =(2n-4)90
But given sum=3060
(2n-4)90=3060
2n-4=3060/90
2n-4=34
2n=38
n=19
.: No. of sides of the polygon is 19. (Ans.)
But given sum=3060
(2n-4)90=3060
2n-4=3060/90
2n-4=34
2n=38
n=19
.: No. of sides of the polygon is 19. (Ans.)
nabilsuraj2004:
are you from ihs
where is it?
ihs
what do you mean by ihs
it is the name of a school
No. I am not from IHS
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