Question

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Answer 1

Answer:

please mark my answer as the brainliest

Answer 2

Answer:

given OB is bisector of angle ABC, so

angle OBC = angle OBA = (1/2)*angle ABC

similarly, OC is bisector of angle ACB, so

angle OCB = angle OCA = (1/2)*angle ACB

In triangle OBC

(I am not using the word angle now)

BOC + OBC + OCB = 180°

BOC = 180° - (OBC + OCB)

BOC = 180° - ((1/2) ABC + (1/2) ACB)

BOC = 180° - 1/2(ABC + ACB)..........(1)

now in ∆ABC

ABC + ACB + BAC = 180°

ABC + ACB = 180° - BAC

ABC + ACB = 180° - A. (BAC can be written as A)

putting this value in (1) we have

BOC = 180° - 1/2(180° -.A)

BOC = 180° - 1/2*180° + 1/2*A

BOC = 180° - 90° + A/2

BOC = 90° + A/2

proved