Question

pls answer this question from the attachment pls​

Answer 1

Answer:

Let

$f(x) = a {x}^{3} + b {x}^{2} + x - 6$

Given

$f( - 2) = 0 \: and \: f(2) = 4 \\ \{ \: x + 2 = 0 \implies \: x = - 2 \\ \: \: \: x - 2 = 0 \implies \: x = 2 \: \}$

So

$a ({ - 2)}^{3} + b { (- 2)}^{2} - 2- 6 = 0 \\ - 8a + 4b = 8 \\ b - 2a = 2 \: \: ..... \: eq1 \: \\ \\ and \\ \\ a {2}^{3} + b {2}^{2} + 2 - 6 = 4 \\ 8 a + 4b = 8 \\ 2a + b = 2 \: ......eq \: 2 \\ \\ add \: both \: eq \\ 2b = 4 \implies \: b = 2 \\ \\ subtract \: \\ - 4a = 0 \implies \: a = 0 \\ so \\ \\ \huge\orange{a = 0 \: \: and \: \: b = 2}$

Answer 2

Answer:

please give me thanks...