Question

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Answer 1

The molecular weight of azide ion is 42.

Thus number of moles of N₃⁻ in 4.2 grams = 0.1 moles

The number of valence electrons in each nitrogen is 5,
so in 3 nitrogens the number of valence electrons is 15

the negative charge on azide ion indicates that there is an extra electron added which resides in the valence shell.

Therefore there are 16 valence electrons in 1 molecule of azide ion.

If N₀ is the Avogadro number,
the number of molecules of azide ion in 1mole = N₀

Thus, the number of valence electrons in 1mole of azide ion = 16N₀

Hence the number of valence electrons in 0.1moles of N₃⁻ = 0.1(16N₀)
                                                                                             = 1.6N₀