Question

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Write a program in Java to find the sum of given series
1+(2^2)/a+(3^3)/(a*a).......................................................to n terms

Answer 1

Explanation:

public static void main(String[] args) {

Scanner scn=new Scanner(System.in);

int n=scn.nextInt(), sum=0;

for(int i=1; i<=n; i++) sum+=fact(i);

System.out.println(sum);

}

Answer 2

Answer:

$import \: java.util.^* \: ;$

$class \: printing$

$\{$

$public \: static \: void \: main \: (String \: args[ \: ] \: )$

$\{$

$Scanner \: sc \: = \: new \: Scanner \: ( \: System.in \: );$

$int \: i \: , \: n \: , \: sum \: ;$

$System.out.println("Please \: enter \: the \: value \: of \: n");$

$n \: = \: sc.nextInt();$

$System.out.println("Please \: enter \: the \: value \: of \: a");$

$a \: = \: sc.nextInt();$

$for(i=1;i < = n;i++)$

$\{$

$sum \: = \: sum \: + \: (Math.pow(i,i)/Math.pow(a,(i-1)));$

$\}$

$System.out.println("Sum\:of\:the\:series\:=\:"+sum);$

$\}$

$\}$

Explanation:

The logic was very simple. You have to just do this:

$\dfrac{i^i}{a^(i-1)}$ until n terms

So, you have to just take the value of n and a from the user and substitute value a and n in the place of a and n in the program.