Math, asked by answermaker25, 4 months ago

pls answer this question I tried many time I didn't get the answer can anyone help with this pls...​ it is so urgent

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Answered by kakarlanikhil108
1

According to the question,

According to the question,angle COA + AOB = 180°

According to the question,angle COA + AOB = 180°70° + AOB = 180°

According to the question,angle COA + AOB = 180°70° + AOB = 180°AOB = 180°- 70°

According to the question,angle COA + AOB = 180°70° + AOB = 180°AOB = 180°- 70°AOB = 110°

According to the question,angle COA + AOB = 180°70° + AOB = 180°AOB = 180°- 70°AOB = 110° &

According to the question,angle COA + AOB = 180°70° + AOB = 180°AOB = 180°- 70°AOB = 110° &angle CAO + AOC = 180°

According to the question,angle COA + AOB = 180°70° + AOB = 180°AOB = 180°- 70°AOB = 110° &angle CAO + AOC = 180°70° + x° =180°

According to the question,angle COA + AOB = 180°70° + AOB = 180°AOB = 180°- 70°AOB = 110° &angle CAO + AOC = 180°70° + x° =180°x° = 180° - 70°

According to the question,angle COA + AOB = 180°70° + AOB = 180°AOB = 180°- 70°AOB = 110° &angle CAO + AOC = 180°70° + x° =180°x° = 180° - 70°x° = 110°

According to the question,angle COA + AOB = 180°70° + AOB = 180°AOB = 180°- 70°AOB = 110° &angle CAO + AOC = 180°70° + x° =180°x° = 180° - 70°x° = 110°Therefore, the answer is 110°

According to the question,angle COA + AOB = 180°70° + AOB = 180°AOB = 180°- 70°AOB = 110° &angle CAO + AOC = 180°70° + x° =180°x° = 180° - 70°x° = 110°Therefore, the answer is 110°Hope this helps you

According to the question,angle COA + AOB = 180°70° + AOB = 180°AOB = 180°- 70°AOB = 110° &angle CAO + AOC = 180°70° + x° =180°x° = 180° - 70°x° = 110°Therefore, the answer is 110°Hope this helps youMark me as brainliest

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