Question

pls answer this question
I will mark it as brainliest​

Answer 1

.........Hello Mate........

Here is answer below,

given values are, tan A = √2 - 1

Now going to solution,

$= > \frac{ \tan( \alpha ) }{1 + \tan {}^{2} ( \alpha ) } \\ = > now \: put \: the \: value \: of \: tan( \alpha) \: in \: above \: eqn \: \\ = > \frac{ \sqrt{2} - 1 }{1 + ( \sqrt{2} - 1) {}^{2} } \\ = > \frac{ \sqrt{2} - 1 }{1 + 2 + 1 - 2 \sqrt{2} } \\ = > \frac{ \sqrt{2} - 1 }{4 - 2 \sqrt{2} } \\ = > \frac{ \sqrt{2 } - 1 }{2(2 - \sqrt{2} )} \\ = > fraction \: rationalization \: \\ = > \frac{ \sqrt{2} - 1 }{4 - 2 \sqrt{2} } \times \frac{ \sqrt{2} + 1}{ \sqrt{2} + 1 } \\ = > \frac{2 - 1}{4 \sqrt{2} - 4 + 4 - 2 \sqrt{2} } \\ = > \frac{1}{2 \sqrt{2} }$

Option( A ) is correct answer.

I hope that helps you,,

@Shahood Alam.....

Mark as Brainlist and follow me I will give more answer.