Question

pls answer this question in maths
chapter-Ratio
R.S Aggarwal
Goyal Brothers Prakashan
No Spam!​

Answer 1

Answer:

A=200. B=240 C=320

Step-by-step explanation:

B:C=3:4=B/C=3/4

let constant of ratio be x. then,

B=3x

C=4x

Then, A=5/6*3x

=5x/2

According to question,

A+B+C= 760

5x/2+3x+4x=760

19x/2=760

x=80

Now,

A=5x\2=5*80/2=200

B=3x=3*80=240

C=4x=4*80=320

Check(optional)

A+B+C=760

200+240+320=760

760=760

rhs=lhs

Answer 2

Answer:

division between them=A=200,B=240,C=320

let a b c be the amounts that are to be divided between A B and C

Thus:A +B +C= 760 (1st equation)

A gets 5/6 of what B gets

a = 5/6 *B

6a = 5b(2nd equation)

Ratio=3:4

B/C = 3/4

4b = 3c (3rd equation)

MULTIPLY (EQN 2) BY 4 AND (EQN 3) BY 5

24a = 15c

a= (15/24)*c

a= (5/8)*c (4th equation)

EQUN 3=

b = (3/4)*c (5th equation)

using equation 4 and equation 5 in equation 1 we get:

(5/8)*c + (3/4)*c + c = 760

5c/8 + 3c/4 + c = 760

LCM:8

(5c+6c+8c)/8= 760

19c =8*760

c =(8*760)/19

c = 320

using eqn 4 and eqn 5 we get

a=(5/8)*320=200

b=(3/4)*320=240

VERIFY:

Sum of A + B + C= 200+240+320=760

B:C=200:240 = 3:4

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