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VedaantArya:
Here, the question has defined a binary operation * between two operands, in the way: x * y = x + y - xy. Note that * does not represent multiplication here. Think of a binary operation as a function that takes in two variables, that is, x * y = f(x, y) = x + y - xy. Now, the question asks the value of (-10) * 5, that is, the value obtained on performing this binary operation on (-10, 5). (...)
So, f(-10, 5) = -10 + 5 - (-10)(5) = -5 + 50 = 45 (1).
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(1) 45
Step-by-step explanation:
Here, the question has defined a binary operation * between two operands, in the way: x * y = x + y - xy. Note that * does not represent multiplication here.
Think of a binary operation as a function that takes in two variables, that is, x * y = f(x, y) = x + y - xy.
Now, the question asks the value of (-10) * 5, that is, the value obtained on performing this binary operation on (-10, 5).
So, f(-10, 5) = -10 + 5 - (-10)(5) = -5 + 50 = 45 (1).
Binary operations are explained at the end of the first chapter of Class XII NCERT (Part I).
This is ICSE class 7 Maths!!!!!!!
xD. I was in ICSE too, we didn't have such scary-looking stuff.
Have you got "binary operations"?
Have you got "binary operations"?
BTW sorry for the complex explanation then.
Don't delete it though - your question is relevant to Class 12th too, and this solution is appropriate for that.
As for your grade, I'll edit in an appropriate solution.
Don't delete it though - your question is relevant to Class 12th too, and this solution is appropriate for that.
As for your grade, I'll edit in an appropriate solution.
(...) Awkwardly, I can't find the edit button.
Here:
It is given that x * y = x + y - xy.
(Note: the * here doesn't correspond to multiplication.)
To apply (-10) * 5, simply replace x with (-10) and y with 5 in the statement given to you.
It becomes: (-10) * 5 = (-10) + 5 - (-10)(5)
So, (-10) * 5 = -10 + 5 + 50 = -5 + 50 = 45 (1).
Apologies for the mess I've made.
Here:
It is given that x * y = x + y - xy.
(Note: the * here doesn't correspond to multiplication.)
To apply (-10) * 5, simply replace x with (-10) and y with 5 in the statement given to you.
It becomes: (-10) * 5 = (-10) + 5 - (-10)(5)
So, (-10) * 5 = -10 + 5 + 50 = -5 + 50 = 45 (1).
Apologies for the mess I've made.
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