Question

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Answer 1

Answer:

$\displaystyle A=\left[\begin{matrix}-3&-4\\2&-3\end{matrix}\right]\left[\begin{matrix}2\\-2\end{matrix}\right]=\left[\begin{matrix}-3\times2+-4\times-2\\2\times2+-3\times-2\end{matrix}\right]=\left[\begin{matrix}-6+8\\4+6\end{matrix}\right]=\left[\begin{matrix}2\\10\end{matrix}\right]$

$\displaystyle 3B=2A-\left[\begin{matrix}12\\-14\end{matrix}\right]=\left[\begin{matrix}4\\20\end{matrix}\right]-\left[\begin{matrix}12\\-14\end{matrix}\right]=\left[\begin{matrix}4-12\\20+14\end{matrix}\right]=\left[\begin{matrix}-8\\34\end{matrix}\right]\\\\\Rightarrow B=\left[\begin{matrix}-8/3\\ 34/3\end{matrix}\right]$