Question

pls answer this question need some help​

Answer 1

Step-by-step explanation:

hope this is helpful for you

Answer 2

Answer:

we have to prove that √2 is irrational

so let us assume that √2 us rational

so, √2=p/q( it can be written in the form of p/q)

thus, p and q are co-primes and qis not equal to 0

now, on squaring both sides,

(√2)²=(p/q)²

2=p²/q²

p²=2q²

p² is divisible by 2

so, p is also divisible by 2(Theo 1)

p= 2×k(any integer)

p=2k

(2k)²= 2q²

2q²= 4k²

q²=2k²

q² is divisible by 2

so, q is also divisible by 2

but this contradicts to the fact that p and q are co-primes

this contradiction has raised due to our wrong assumption that √2 is rational

thus, √2 is irrational

hope this helps

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