pls answer this question no. 10 pls
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x=25°
It's may be right
It's may be right
anyone39:
but how
Angle made by center of circle=2× angle made to its circumference .....So.... Angle COB=2angle BDC
yes
Answered by
1
Hey friend ...
it's easy ...
•°•<AOC=130°{given )_______1)
and <AOB=180° (from linear pair )-----2)
now. ..<AOC+<BOC=<AOB {we can write }
(given } and from 1 and 2 we get .
130°+<BOC=180°
<BOC=50°
<BOC=2×<BDC(According to this theorem )
[•°•the angle substances by an arc at the centre is twice the angle subtended on the remaining part of the circle ]
So. BOC=x°=50°/2=25 °
Answer
Hope it helps you..!
€rajukumar111
it's easy ...
•°•<AOC=130°{given )_______1)
and <AOB=180° (from linear pair )-----2)
now. ..<AOC+<BOC=<AOB {we can write }
(given } and from 1 and 2 we get .
130°+<BOC=180°
<BOC=50°
<BOC=2×<BDC(According to this theorem )
[•°•the angle substances by an arc at the centre is twice the angle subtended on the remaining part of the circle ]
So. BOC=x°=50°/2=25 °
Answer
Hope it helps you..!
€rajukumar111
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