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Here's the answer...
Hope it helps you...
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x - log(16×3) + 3log2 = 1÷3[log (5^3)] - log3
x - [ log16 + log3] + 3log2 = 1÷3[3log5] - log3
x- log(2^4) - log3 + 3log2 = log5 - log3
x - 4log2 + 3log2 = log5
x = log5 + log2
x = 0.6989 + 0.3010
x = 0.9999
hope it helps you....
x - [ log16 + log3] + 3log2 = 1÷3[3log5] - log3
x- log(2^4) - log3 + 3log2 = log5 - log3
x - 4log2 + 3log2 = log5
x = log5 + log2
x = 0.6989 + 0.3010
x = 0.9999
hope it helps you....
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