Question

Pls answer this question
Q. 35

Answer 1

Answer:

k=20, take x+1=0 x=1, substitute in first polynomial , x-2=0,  x=2 substitute  in second polynomial

Step-by-step explanation:

f[x]=[-1]³+2 k[-1]³-5[-1]²-7=R1

G[X]=[2]³+[2]²-12[2]+6K=R2

on solving you get ,

-14-2k=R1

-12+6k=R2

given that ,

2R1+R2-12=0

2[-14-2K]+[-12+6K]=0

-40+2K=0

-40=-2K

-40/-2=K

K=20