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Q A 50 g sample of naoh is added to 500 ml of hcl with molarity 0.8M to nutrilize it find the percentage purity of naoh
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Answer:
Explanation:
Sodium carbonate reacts with hydrochloric acid:
N
a
2
C
O
3
(
s
)
+
2
H
C
l
(
a
q
)
→
2
N
a
C
l
(
a
q
)
+
C
O
2
(
g
)
+
H
2
O
(
l
)
We can find the number of moles of
HCl
before the reaction.
We then use the titration result to find the number of moles remaining after the reaction.
By subtracting the two we can get the number of moles of
HCl
which have reacted.
From the equation we can find the number of moles of
Na
2
CO
3
.
From this we get the mass of
Na
2
CO
3
.
We can then work out the percentage purity.
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