Math, asked by GNOATGAMINGYT, 13 days ago

Pls answer this question qs no. 16
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Answers

Answered by gjkl4820
1

Answer:

Step-by-step explanation:

After trying my best, I'm still not able yo get the answer as 1. Please check your question once again or look at other material.

Reference:

Step 1: Cosec^2=1/sin^2. Cot^2=cos^2/sin^2

Step 2: Cancelling common functions

Step 3: Taking LCM

Step 4: sin^2+cos^2=1

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Answered by kiran12355
1

Step-by-step explanation:

cos^Bcosec^2@-sin^2Bcot^2B-cos^2Bcot^2@+sin^2Bcosec^2@

(cos^2B/sin^2@)-(sin^2B*cos^2B/sin^2B)-(cos^2B*cos^2@/sin^2@)+(sin^2B/sin^2@)

(cos^2B/sin^2@)+(sin^2B/sin^2@)-(cos^2B)-(cos^2B*cos^2@/sin^2@)

(cos^2B+sin^2B/sin^2B)-(cos^2B)-(cos^2B*cot^2@)

cosec^2B-cos^2B-cos^2B(cos^2@/sin^2@)

cosec^2B-cos^2B(1+cos^2@/sin^2@)

cosec^2B-cos^2B(sin^2@+cos^2@/sin^2@)

cosec^2B-cos^2B(1/sin^2@)

cosec^2B-cos^2B(coesc^2B)

cosec^2B(1-cos^2B)

coesc^2B*sin^2B

sin^2B/sin^2B

=1

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