Question

pls answer this question so important​

Answer 1

Sol: Area of the trapezium = h/2 (a + b)

where a and b are the parallel sides and h is the perpendicualr distance between the parallel sides.

Area of the trapezium ABCD = AB/2 (AD + BC)

24.5 = (AB/2) (10 + 4)

49 = AB (14)

AB = 3.5 cm

Radius of the quadrant of the circle = AB = 3.5 cm

Area of the quadrant of the circle = (1/4) (πr2) = (1/4) (22/7 x 3.5 x 3.5) = 9.625 cm2

Area of the shaded region = Area of the trapezium - Area of the quadrant of the circle = 24.5 - 9.625 = 14.875 cm2

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Answer 2

Area of the sector =

$\frac{1}{4} \times \pi {r}^{2}$

$\frac{1}{4} \times \frac{22}{7} \times {4}^{2}$

= 12.571 cm sq.

Area of the trapezium is 24.5 sq.

Area of the shaded region = 24.5 - 12.571