Question

pls answer this question...
thanks for help​

Answer 1

Step-by-step explanation:

2x-5+x-10=90°

3x-15=90

3x=90+15

3x=105

x=105/3

x=35

apc=2 x35 -5

=70-5

=65

boc=35-10

=25

hope it helps you

Answer 2

AO PERPENDICULAR TO OB

THUS,ANGLE AOB =90°

SO,

angle aoc+angle boc=90°

2x-5+x-10=90°

3x-15=90

3x=105

x=105/3

x=35

so,angle aoc=2x-5 ; x=35 ; 2×35-5 ; 65°

angle boc=x-5; 35-10=25°