Question

Pls answer this question
The distance of the point (-3,4) from y axisis

Answer 1

Answer:

take coordinate of y axis as (0,y)

on apply distance formula

we get √ y2-2y+25.

since coordinate if y axis is not given take it as origin

so distance is 5

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Answer 2

Answer:

The distance between the point (-3, 4) and y-axis is 3 units.

Step-by-step explanation:

The formula to compute distance between two points is:

$d=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$

Given:

P = (-3, 4)

Y = y-axis = (0, 4)

*Since the point is on the y-axis the x co-ordinate is 0.

Compute he distance as follows:

$d=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}\\=\sqrt{(0-(-3))^{2}+(4-4)^{2}}\\=\sqrt{9}\\=3$

Thus, the distance between the point (-3, 4) and y-axis is 3 units.