Math, asked by mimaratha, 1 year ago

pls answer this question. this is the second time i am asking this question

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Answered by adithya02
2
AQ = AR (tangents from external points to a circle are equal)
BQ = BP (,,)
PC = CR (,,)

Now perimeter of ABC = AB + BC + AC
= AB + BP + PC + AC
= AB + BQ + CR + AC
= AQ + AR
= 2AQ ( Because AQ = AR )

Hence AQ = 1/2 (Perimeter ABC)

Hope this helps!
Answered by Hasti152002
2
Hey... I think this can be ur answer!!

Given :AQ & AR are tangents

To prove : AQ=1/2(PERIMETER OF ABC)

Proof :
BP =BQ and CP =CR (tangents)
Now,
Perimeter of ABC = AB +AC +BC

AQ=AB+BQ
AR =AC +CR
Adding both the equations,
AQ+AR =AB +BQ+AC +CR
2AQ=AB +AC +BP +CP
2AQ=AB +AC +BC
2AQ =PERIMETER OF ABC
AQ =1/2(PERIMETER OF ABC

HENCE PROVED...

Hope it helps you dear ☺️☺️
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