Question

pls answer this question


today's algebra SSC paper question

help

​

Answer 1

$\large\boxed{\fcolorbox{blue}{yellow} {Answer}}$

The cost price of the toy is ₹ 20.

$\large\boxed{\fcolorbox{blue}{yellow} {Step - by - step explanation }}$

S. P. of the toy = ₹ 24. [Given]

Let the C. P. of the toy be ₹ x.

.°. Gain % = x %

Gain % =

$\frac{sp \: - \: cp \: }{cp} \times 100 \\ \\ = > \: x = \frac{24 - x}{x} \times 100$

$= > {x}^{2} + 100x - 2400 = 0 \\ = > {x}^{2} + 120x - 20x - 2400 = 0 \\ = > (x + 120) \: (x - 20) = 0$

.°. x + 120 = 0 or x - 20 = 0

=> x = - 120 or x = 20

As cost can't be negative,

.°. Cost price = x = ₹ 20.

Hope it helps!

$<marquee> Mark as brainliest ✔️</marquee>$

Answer 2

Answer:

Hey mate

Explanation:

The cost price of toy is RS.20

MARK ME AS BRAINLEST