Question

pls answer this question very urgent ( chapter:simultaneous equations)​

Answer 1

MARK BRAINLIEST.

MARK BRAINLIEST.

Answer 2

$\frac{3x}{2} - \frac{5y}{3} + 2 = \\ \frac{9x - 10y + 12}{6} = 0 \\ 9x- 10y + 12 = 0 \\ 9x = 10y - 12 \\ x = \frac{10y - 12}{9}$

putting the value of x in another equation

$\frac{x}{3} + \frac{y}{2} = 2 \frac{1}{6} \\ \frac{2x + 3y}{6} = \frac{13}{6} \\ 2x + 3y = 13 \\ 2 \times ( \frac{10y - 12}{9} ) + 3y = 13 \\ \frac{20y - 24}{9} + 3y = 13 \\ \frac{20y - 24 + 27y}{9} = 13 \\ 47y - 24 = 117 \\ 47y = 117 + 24 \\ 47y = 141 \\ y = \frac{141}{47} \\ y = 3$

then x will be

$x = \frac{10y - 12}{9} \\ x = \frac{(10 \times 3 )- 12}{9} \\ x = \frac{30 - 12}{9} \\ x = \frac{18}{9} \\ x = 2$