Question

Pls answer this question with explanation

Answer 1

Answer:

let α =a-b, β = a and ¥(Gama)= a+b.and compare equation : a= 2, b= -6 ,c =5 ,D = -7 .

then, according to 1st relation :

α+β+¥ = -b/a

a+b +a +a-b = -( -6)/2

3a = 3

a=1.

hence ,the value of a is 1.

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