Question

pls answer this question with explanation​

Answer 1

$\huge{\blue{\textbf{SOLUTION}}}$

Let's first take the three resistors in between,

We can see that those 3 resistors are in parallel,

Hence, the effective resistance in those 3 resistors is

$\frac{1}{Rp}$= $\frac{1}{R}$+ $\frac{1}{R}$ +$\frac{1}{R}$

$\frac{1}{Rp}$ = $\frac{3}{R}$

Rp= $\frac{R}{3}$

From the figure, we can observe that the resistors in straight line to A and B are in series with the three resistors connected in parallel.

Hence, the effective resistance is,

Rs = R + $\frac{R}{3}$+ R

Here, LCM is 3

Rs = $\frac{3R+R+3R}{3}$

Rs = $\frac{7R}{3}$

Hence the resisitance between A and B is $\frac{7R}{3}$

Answer : Option A

Answer 2

your correct ans is option a